\(\int \frac {1}{x^4 (c+a^2 c x^2)^2 \arctan (a x)^2} \, dx\) [558]

Optimal result

Integrand size = 22, antiderivative size = 22 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=-\frac {1}{a c^2 x^4 \arctan (a x)}+\frac {a}{c^2 x^2 \arctan (a x)}-\frac {a^3}{c^2 \left (1+a^2 x^2\right ) \arctan (a x)}-\frac {a^3 \text {Si}(2 \arctan (a x))}{c^2}-\frac {4 \text {Int}\left (\frac {1}{x^5 \arctan (a x)},x\right )}{a c^2}+\frac {2 a \text {Int}\left (\frac {1}{x^3 \arctan (a x)},x\right )}{c^2} \]

[Out]

-1/a/c^2/x^4/arctan(a*x)+a/c^2/x^2/arctan(a*x)-a^3/c^2/(a^2*x^2+1)/arctan(a*x)-a^3*Si(2*arctan(a*x))/c^2-4*Uni
ntegrable(1/x^5/arctan(a*x),x)/a/c^2+2*a*Unintegrable(1/x^3/arctan(a*x),x)/c^2

Rubi [N/A]

Not integrable

Time = 0.28 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=\int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx \]

[In]

Int[1/(x^4*(c + a^2*c*x^2)^2*ArcTan[a*x]^2),x]

[Out]

-(1/(a*c^2*x^4*ArcTan[a*x])) + a/(c^2*x^2*ArcTan[a*x]) - a^3/(c^2*(1 + a^2*x^2)*ArcTan[a*x]) - (a^3*SinIntegra
l[2*ArcTan[a*x]])/c^2 - (4*Defer[Int][1/(x^5*ArcTan[a*x]), x])/(a*c^2) + (2*a*Defer[Int][1/(x^3*ArcTan[a*x]),
x])/c^2

Rubi steps \begin{align*} \text {integral}& = -\left (a^2 \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx\right )+\frac {\int \frac {1}{x^4 \left (c+a^2 c x^2\right ) \arctan (a x)^2} \, dx}{c} \\ & = -\frac {1}{a c^2 x^4 \arctan (a x)}+a^4 \int \frac {1}{\left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx-\frac {4 \int \frac {1}{x^5 \arctan (a x)} \, dx}{a c^2}-\frac {a^2 \int \frac {1}{x^2 \left (c+a^2 c x^2\right ) \arctan (a x)^2} \, dx}{c} \\ & = -\frac {1}{a c^2 x^4 \arctan (a x)}+\frac {a}{c^2 x^2 \arctan (a x)}-\frac {a^3}{c^2 \left (1+a^2 x^2\right ) \arctan (a x)}-\left (2 a^5\right ) \int \frac {x}{\left (c+a^2 c x^2\right )^2 \arctan (a x)} \, dx-\frac {4 \int \frac {1}{x^5 \arctan (a x)} \, dx}{a c^2}+\frac {(2 a) \int \frac {1}{x^3 \arctan (a x)} \, dx}{c^2} \\ & = -\frac {1}{a c^2 x^4 \arctan (a x)}+\frac {a}{c^2 x^2 \arctan (a x)}-\frac {a^3}{c^2 \left (1+a^2 x^2\right ) \arctan (a x)}-\frac {4 \int \frac {1}{x^5 \arctan (a x)} \, dx}{a c^2}+\frac {(2 a) \int \frac {1}{x^3 \arctan (a x)} \, dx}{c^2}-\frac {\left (2 a^3\right ) \text {Subst}\left (\int \frac {\cos (x) \sin (x)}{x} \, dx,x,\arctan (a x)\right )}{c^2} \\ & = -\frac {1}{a c^2 x^4 \arctan (a x)}+\frac {a}{c^2 x^2 \arctan (a x)}-\frac {a^3}{c^2 \left (1+a^2 x^2\right ) \arctan (a x)}-\frac {4 \int \frac {1}{x^5 \arctan (a x)} \, dx}{a c^2}+\frac {(2 a) \int \frac {1}{x^3 \arctan (a x)} \, dx}{c^2}-\frac {\left (2 a^3\right ) \text {Subst}\left (\int \frac {\sin (2 x)}{2 x} \, dx,x,\arctan (a x)\right )}{c^2} \\ & = -\frac {1}{a c^2 x^4 \arctan (a x)}+\frac {a}{c^2 x^2 \arctan (a x)}-\frac {a^3}{c^2 \left (1+a^2 x^2\right ) \arctan (a x)}-\frac {4 \int \frac {1}{x^5 \arctan (a x)} \, dx}{a c^2}+\frac {(2 a) \int \frac {1}{x^3 \arctan (a x)} \, dx}{c^2}-\frac {a^3 \text {Subst}\left (\int \frac {\sin (2 x)}{x} \, dx,x,\arctan (a x)\right )}{c^2} \\ & = -\frac {1}{a c^2 x^4 \arctan (a x)}+\frac {a}{c^2 x^2 \arctan (a x)}-\frac {a^3}{c^2 \left (1+a^2 x^2\right ) \arctan (a x)}-\frac {a^3 \text {Si}(2 \arctan (a x))}{c^2}-\frac {4 \int \frac {1}{x^5 \arctan (a x)} \, dx}{a c^2}+\frac {(2 a) \int \frac {1}{x^3 \arctan (a x)} \, dx}{c^2} \\ \end{align*}

Mathematica [N/A]

Not integrable

Time = 2.58 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=\int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx \]

[In]

Integrate[1/(x^4*(c + a^2*c*x^2)^2*ArcTan[a*x]^2),x]

[Out]

Integrate[1/(x^4*(c + a^2*c*x^2)^2*ArcTan[a*x]^2), x]

Maple [N/A] (verified)

Not integrable

Time = 21.47 (sec) , antiderivative size = 22, normalized size of antiderivative = 1.00

\[\int \frac {1}{x^{4} \left (a^{2} c \,x^{2}+c \right )^{2} \arctan \left (a x \right )^{2}}d x\]

[In]

int(1/x^4/(a^2*c*x^2+c)^2/arctan(a*x)^2,x)

[Out]

int(1/x^4/(a^2*c*x^2+c)^2/arctan(a*x)^2,x)

Fricas [N/A]

Not integrable

Time = 0.23 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.82 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{2} x^{4} \arctan \left (a x\right )^{2}} \,d x } \]

[In]

integrate(1/x^4/(a^2*c*x^2+c)^2/arctan(a*x)^2,x, algorithm="fricas")

[Out]

integral(1/((a^4*c^2*x^8 + 2*a^2*c^2*x^6 + c^2*x^4)*arctan(a*x)^2), x)

Sympy [N/A]

Not integrable

Time = 1.42 (sec) , antiderivative size = 44, normalized size of antiderivative = 2.00 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=\frac {\int \frac {1}{a^{4} x^{8} \operatorname {atan}^{2}{\left (a x \right )} + 2 a^{2} x^{6} \operatorname {atan}^{2}{\left (a x \right )} + x^{4} \operatorname {atan}^{2}{\left (a x \right )}}\, dx}{c^{2}} \]

[In]

integrate(1/x**4/(a**2*c*x**2+c)**2/atan(a*x)**2,x)

[Out]

Integral(1/(a**4*x**8*atan(a*x)**2 + 2*a**2*x**6*atan(a*x)**2 + x**4*atan(a*x)**2), x)/c**2

Maxima [N/A]

Not integrable

Time = 0.30 (sec) , antiderivative size = 107, normalized size of antiderivative = 4.86 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{2} x^{4} \arctan \left (a x\right )^{2}} \,d x } \]

[In]

integrate(1/x^4/(a^2*c*x^2+c)^2/arctan(a*x)^2,x, algorithm="maxima")

[Out]

-((a^3*c^2*x^6 + a*c^2*x^4)*arctan(a*x)*integrate(2*(3*a^2*x^2 + 2)/((a^5*c^2*x^9 + 2*a^3*c^2*x^7 + a*c^2*x^5)
*arctan(a*x)), x) + 1)/((a^3*c^2*x^6 + a*c^2*x^4)*arctan(a*x))

Giac [N/A]

Not integrable

Time = 89.12 (sec) , antiderivative size = 3, normalized size of antiderivative = 0.14 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{2} x^{4} \arctan \left (a x\right )^{2}} \,d x } \]

[In]

integrate(1/x^4/(a^2*c*x^2+c)^2/arctan(a*x)^2,x, algorithm="giac")

[Out]

sage0*x

Mupad [N/A]

Not integrable

Time = 0.43 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.09 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^2 \arctan (a x)^2} \, dx=\int \frac {1}{x^4\,{\mathrm {atan}\left (a\,x\right )}^2\,{\left (c\,a^2\,x^2+c\right )}^2} \,d x \]

[In]

int(1/(x^4*atan(a*x)^2*(c + a^2*c*x^2)^2),x)

[Out]

int(1/(x^4*atan(a*x)^2*(c + a^2*c*x^2)^2), x)